Complete the following reactions:
$1. CH_4 + I_2 \rightleftharpoons ?$
$2. CH_3-CH_3 + Cl_2 \xrightarrow{h\nu} ?$
$1. CH_4 + I_2 \rightleftharpoons ?$
$2. CH_3-CH_3 + Cl_2 \xrightarrow{h\nu} ?$
(N/A) The reaction of methane with iodine is reversible:
$CH_4 + I_2 \rightleftharpoons CH_3I + HI$
To drive this reaction in the forward direction,an oxidizing agent like $HIO_3$ is used to remove $HI$:
$5HI + HIO_3 \rightarrow 3I_2 + 3H_2O$
The controlled chlorination of ethane is a free radical substitution reaction:
$CH_3-CH_3 + Cl_2 \xrightarrow{h\nu} CH_3-CH_2Cl + HCl$
$CH_4 + I_2 \rightleftharpoons CH_3I + HI$
To drive this reaction in the forward direction,an oxidizing agent like $HIO_3$ is used to remove $HI$:
$5HI + HIO_3 \rightarrow 3I_2 + 3H_2O$
The controlled chlorination of ethane is a free radical substitution reaction:
$CH_3-CH_3 + Cl_2 \xrightarrow{h\nu} CH_3-CH_2Cl + HCl$
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MediumNEET 2019
View SolutionAssertion $(A):$ Sodium acetate on Kolbe's electrolysis gives ethane.
Reason $(R):$ Methyl free radical is formed at cathode.
Reason $(R):$ Methyl free radical is formed at cathode.
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